[摘要]【前 言】:这个软件有很多地方不明白,所以发出来和大家探讨一下!(在这里也要谢谢安靖) 【下载页面】http://www.softreg.com.cn/shareware_view.asp?i...
【前 言】:这个软件有很多地方不明白,所以发出来和大家探讨一下!(在这里也要谢谢安靖)
【下载页面】
http://www.softreg.com.cn/shareware_view.asp?id=/3E781F2B-1927-46BD-BB4E-567A2FE09680/
【文章作者】:辉仔Yock[DFCG][YCG]
【作者声明】:本人发表这篇文章只是为了学习和研究!!!请不用于商业用途或是将本文方法制作的注册机任意传播,读者看了文章后所做的事情与我无关,我也不会负责,请读者看了文章后三思而后行!最后希望大家在经济基础好的时候,支持共享软件!
【破解工具】:OLLYDBG W32Dasm
—————————————————————————————————
【过 程】:
主程序SFCAPCaster.exe没有加壳,事用Microsoft Visual C++ 6.0编写的!
用W32dasm反汇编,根据参考字串很快找到关键!
用OLLYDBG加载SFCAPCaster.exe
选择帮助-->注册-->输入用户名Yock196(用户名要大于5位)-->邮箱地址(可以不填,下面不做运算!-->输入20位的假注册码KHSC-987654321ABCDEF(开头五位一定要是"KHSC-")
下断点004147D4来到下面:
:004147BF E83AE40100 call 00432BFE
//这里事取得用户名位数
:004147C4 8B07 mov eax, dword ptr [edi]
:004147C6 C744242000000000 mov [esp+20], 00000000
:004147CE 8B40F8 mov eax, dword ptr [eax-08]
:004147D1 83F805 cmp eax, 00000005
//比较用户名是否小于5位
:004147D4 7D13 jge 004147E9
:004147D6 6A00 push 00000000
:004147D8 6A10 push 00000010
* Possible StringData Ref from Data Obj ->"请输入长度大于5的用户名称"
:004147DA 68A05B4500 push 00455BA0
:004147DF E8CF410200 call 004389B3
:004147E4 E91E010000 jmp 00414907
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:004147D4(C)
:004147E9 8D4C2410 lea ecx, dword ptr [esp+10]
:004147ED 8D7E5C lea edi, dword ptr [esi+5C]
:004147F0 6A05 push 00000005
:004147F2 51 push ecx
:004147F3 8BCF mov ecx, edi
:004147F5 E8B18A0100 call 0042D2AB
:004147FA 8B00 mov eax, dword ptr [eax]
* Possible StringData Ref from Data Obj ->"KHSC-"
:004147FC 68985B4500 push 00455B98
:00414801 50 push eax
:00414802 E8F59E0000 call 0041E6FC
//比较注册码的前面五位是否"KHSC-"
:00414807 83C408 add esp, 00000008
:0041480A 85C0 test eax, eax
:0041480C 7511 jne 0041481F
//不是就跳下去出错
:0041480E 8B17 mov edx, dword ptr [edi]
:00414810 837AF814 cmp dword ptr [edx-08], 00000014
//比较注册码是否等于20位
:00414814 0F95C0 setne al
:00414817 84C0 test al, al
:00414819 7504 jne 0041481F
//不是的话跳下去出错
:0041481B 32DB xor bl, bl
:0041481D EB02 jmp 00414821
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
:0041480C(C), :00414819(C)
:0041481F B301 mov bl, 01
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:0041481D(U)
:00414821 8D4C2410 lea ecx, dword ptr [esp+10]
:00414825 E85FE60100 call 00432E89
:0041482A 84DB test bl, bl
:0041482C 7413 je 00414841
//输入的注册码如果不符合上面的条件就不跳走!
//符合反之
//这里可以说是一个暗桩,我第一次以为这样注册成功了!
//其实不是的,符合上面的条件,但不是真的注册码一样是未注册!
:0041482E 6A00 push 00000000
:00414830 6A10 push 00000010
* Possible StringData Ref from Data Obj ->"注册失败!"
:00414832 688C5B4500 push 00455B8C
:00414837 E877410200 call 004389B3
:0041483C E9C6000000 jmp 00414907
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:0041482C(C) //上面来到这里!
......
......
//省略一部分用处不大的代码
:0041488D 8D442418 lea eax, dword ptr [esp+18]
:00414891 50 push eax
//用户名
:00414892 E829090000 call 004151C0
//来到这里是把我的用户名经过运算后得出一串数字"298103222272636"
//但是感觉上用处不大,我认为根本就没有!
:00414897 83C40C add esp, 0000000C
:0041489A 50 push eax
:0041489B 8D4C2410 lea ecx, dword ptr [esp+10]
:0041489F C644242402 mov [esp+24], 02
:004148A4 E819E70100 call 00432FC2
:004148A9 8D4C2410 lea ecx, dword ptr [esp+10]
:004148AD C644242000 mov [esp+20], 00
:004148B2 E8D2E50100 call 00432E89
:004148B7 51 push ecx
:004148B8 8D542410 lea edx, dword ptr [esp+10]
:004148BC 8BCC mov ecx, esp
:004148BE 89642418 mov dword ptr [esp+18], esp
:004148C2 52 push edx
:004148C3 E836E30100 call 00432BFE
:004148C8 8BCE mov ecx, esi
:004148CA E861000000 call 00414930
:004148CF 6A00 push 00000000
:004148D1 8BCE mov ecx, esi
:004148D3 E838010000 call 00414A10
:004148D8 8BCE mov ecx, esi
:004148DA E8E1030000 call 00414CC0
//根据W32Dasm的提示得知这个CALL里面是注册成功但出的窗口!
//跟进去!
:004148DF 8BCE mov ecx, esi
:004148E1 E87A030000 call 00414C60
//根据W32Dasm的提示得知这个CALL里面是注册成功但出的窗口!
//跟进去!
:004148E6 8B461C mov eax, dword ptr [esi+1C]
:004148E9 6A00 push 00000000
:004148EB 6A00 push 00000000
:004148ED 6892040000 push 00000492
:004148F2 50 push eax
* Reference To: USER32.SendMessageA, Ord:0214h
:004148F3 FF1574654400 Call dword ptr [00446574]
//这个地方是最不明白的了!
//用"安靖"的注册码注册就在这里但出成功的窗口!
//用我自己追出来的注册码,这里是没有反映的!但也能注册成功!
//还请高手指点!
:004148F9 8BCE mov ecx, esi
:004148FB E86DE00100 call 0043296D
:00414900 8BCE mov ecx, esi
:00414902 E81EF60100 call 00433F25
------------------------------------------------------------------
上面004148DA的CALL来到这里:
* Referenced by a CALL at Address:
:004148DA
:00414CC0 51 push ecx
:00414CC1 56 push esi
:00414CC2 8BF1 mov esi, ecx
:00414CC4 57 push edi
:00414CC5 8D442408 lea eax, dword ptr [esp+08]
:00414CC9 6A05 push 00000005
:00414CCB 50 push eax
:00414CCC 8D8EF4010000 lea ecx, dword ptr [esi+000001F4]
:00414CD2 E8D4850100 call 0042D2AB
:00414CD7 8B00 mov eax, dword ptr [eax]
:00414CD9 50 push eax
:00414CDA E8129A0000 call 0041E6F1
:00414CDF 83C404 add esp, 00000004
:00414CE2 8D4C2408 lea ecx, dword ptr [esp+08]
:00414CE6 8BF8 mov edi, eax
:00414CE8 E89CE10100 call 00432E89
:00414CED 8B8EE8010000 mov ecx, dword ptr [esi+000001E8]
:00414CF3 51 push ecx
:00414CF4 E887020000 call 00414F80
:00414CF9 83C404 add esp, 00000004
:00414CFC 3BF8 cmp edi, eax
//关键比较...
//EDI和EAX寄存器分别存着真假注册码的前五位数的十六进制值!
:00414CFE 8986E8010000 mov dword ptr [esi+000001E8], eax
:00414D04 7509 jne 00414D0F
//这里跳走的话就...
:00414D06 6A01 push 00000001
:00414D08 8BCE mov ecx, esi
:00414D0A E8B1FEFFFF call 00414BC0
//这里进去有三个跳转,这三个跳转不跳的话就出现注册成功窗口!
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:00414D04(C)
:00414D0F 5F pop edi
:00414D10 5E pop esi
:00414D11 59 pop ecx
:00414D12 C3 ret
------------------------------------------------------------------
上面004148E1的CALL来到这里:
* Referenced by a CALL at Address:
:004148E1
:00414C60 51 push ecx
:00414C61 56 push esi
:00414C62 57 push edi
:00414C63 8BF1 mov esi, ecx
:00414C65 6A05 push 00000005
:00414C67 8D44240C lea eax, dword ptr [esp+0C]
:00414C6B 6A05 push 00000005
:00414C6D 50 push eax
:00414C6E 8D8EF4010000 lea ecx, dword ptr [esi+000001F4]
:00414C74 E820850100 call 0042D199
:00414C79 8B00 mov eax, dword ptr [eax]
:00414C7B 50 push eax
:00414C7C E8709A0000 call 0041E6F1
:00414C81 83C404 add esp, 00000004
:00414C84 8D4C2408 lea ecx, dword ptr [esp+08]
:00414C88 8BF8 mov edi, eax
:00414C8A E8FAE10100 call 00432E89
:00414C8F 8B8EEC010000 mov ecx, dword ptr [esi+000001EC]
:00414C95 51 push ecx
:00414C96 E8B5030000 call 00415050
:00414C9B 83C404 add esp, 00000004
:00414C9E 3BF8 cmp edi, eax
//和上面一样,关键比较...
//EDI和EAX寄存器分别存着真假注册码的前五位数的十六进制值!
:00414CA0 8986EC010000 mov dword ptr [esi+000001EC], eax
:00414CA6 7509 jne 00414CB1
:00414CA8 6A02 push 00000002
:00414CAA 8BCE mov ecx, esi
:00414CAC E80FFFFFFF call 00414BC0
//和上面一样
//这里进去有三个跳转,这三个跳转不跳的话就出现注册成功窗口!
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:00414CA6(C)
:00414CB1 5F pop edi
:00414CB2 5E pop esi
:00414CB3 59 pop ecx
:00414CB4 C3 ret
------------------------------------------------------------------
这里就是00414CAC和00414D0A的CALL来到的地方:
* Referenced by a CALL at Addresses:
:00414586 , :00414CAC , :00414D0A
:00414BC0 56 push esi
:00414BC1 8BF1 mov esi, ecx
:00414BC3 E8CCA20200 call 0043EE94
:00414BC8 8B5004 mov edx, dword ptr [eax+04]
:00414BCB 8B442408 mov eax, dword ptr [esp+08]
:00414BCF 48 dec eax
:00414BD0 7452 je 00414C24
:00414BD2 48 dec eax
:00414BD3 7436 je 00414C0B
//我追出来的正确注册码和"安靖"的注册码在这里都跳走了!
:00414BD5 48 dec eax
:00414BD6 0F8580000000 jne 00414C5C
:00414BDC 6A00 push 00000000
:00414BDE 6A01 push 00000001
:00414BE0 8BCA mov ecx, edx
:00414BE2 C7825802000001000000 mov dword ptr [ebx+00000258], 00000001
:00414BEC E8AFFFFEFF call 00404BA0
:00414BF1 6A00 push 00000000
:00414BF3 6A00 push 00000000
* Possible StringData Ref from Data Obj ->"注册成功, 请重新启动程序!"
:00414BF5 68C05B4500 push 00455BC0
:00414BFA E8B43D0200 call 004389B3
:00414BFF 6A00 push 00000000
* Reference To: USER32.PostQuitMessage, Ord:01E0h
:00414C01 FF1564644400 Call dword ptr [00446464]
:00414C07 5E pop esi
:00414C08 C20400 ret 0004
------------------------------------------------------------------
【总 结】:
我追出的注册码(邮箱不填也可以):
Yock196
KHSC-3518239909*****(后面五位随便)
安靖兄的注册码:
anjing
KHSC-351821842415032
注册信息保存在C:\WINDOWS\SYSTEM\SysXCasterDrv.sys
用我追出来的注册码按注册后没有反应(但也能成功!)
用安靖兄的注册码按注册后会弹出"注册成功, 请重新启动程序!"的框!
我想可能是我没有追到核心,所以想和大家探讨一下!
我问过安靖了,可是没有解决问题!好没头绪,希望又朋友能帮我看看!
最后在这里真心感谢你花了那么多时间看这篇文章!谢谢了...
网络的神奇作用吸引着越来越多的用户加入其中,正因如此,网络的承受能力也面临着越来越严峻的考验―从硬件上、软件上、所用标准上......,各项技术都需要适时应势,对应发展,这正是网络迅速走向进步的催化剂。
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